Proposition 5.1.4: Characterizing Open Sets |
Let U |
Each U n is an interval: take any two points a and b in U n. Being in the same equivalence classes, a and b must be related. But then the whole line segment between a and b is contained in U n as well. Since a and b were arbitrary, U n is indeed an interval.
Each U n is open: take any
x
U n.
Then x
U, and
since U is open, there exists an
> 0 such that
( x -
,
x +
)
is contained in U. But clearly each point in that interval is
related to x, hence this neighborhood is contained in
U n, proving that U n is open.
There are only countably many U n:
This seems the hard part. But, each U n must
contain at least one different rational number.
Why ? Since there are only
countably many rational numbers, there can only be countably many of
the U n's (since they are disjoint).