Proposition 5.1.4: Characterizing Open Sets
 R be  
an arbitrary open set. Then there are countably many pairwise  
disjoint open intervals  
U n such that  
U =
 R be  
an arbitrary open set. Then there are countably many pairwise  
disjoint open intervals  
U n such that  
U =  
 U n
 U n 
 
 
Proof:
This proposition is rather interesting, giving a complete description of any possible open set in the real line. To prove it, we will make use of equivalence relations and classes again. First, let us define a relation on U:- if a and b are in U, we say that a ~ b if the whole line segment between a and b is also contained in U.
 Is this relation indeed an  
equivalence relation ? Assuming that it is, we know immediately that  
U equals the union of the equivalence classes, and the  
equivalence classes are pairwise disjoint. Denote those equivalent  
classes by  
U n
 Is this relation indeed an  
equivalence relation ? Assuming that it is, we know immediately that  
U equals the union of the equivalence classes, and the  
equivalence classes are pairwise disjoint. Denote those equivalent  
classes by  
U n 
 
Each U n is an interval: take any two points a and b in U n. Being in the same equivalence classes, a and b must be related. But then the whole line segment between a and b is contained in U n as well. Since a and b were arbitrary, U n is indeed an interval.
 
Each U n is open: take any  
x  U n. 
Then x
 
   U n. 
Then x  U, and  
since U is open, there exists an
 U, and  
since U is open, there exists an  
 >  0 such that  
( x -
 >  0 such that  
( x -  ,  
     x +
,  
     x +  )  
is contained in U. But clearly each point in that interval is  
related to x, hence this neighborhood is contained in  
U n, proving that U n is open.
)  
is contained in U. But clearly each point in that interval is  
related to x, hence this neighborhood is contained in  
U n, proving that U n is open. 
 
 
There are only countably many U n:  
This seems the hard part. But, each U n must  
contain at least one different rational number.  
 Why ? Since there are only  
countably many rational numbers, there can only be countably many of  
the U n's (since they are disjoint).
 Why ? Since there are only  
countably many rational numbers, there can only be countably many of  
the U n's (since they are disjoint). 
 
 
 
 
 
   
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