Examples 5.1.2(a):
 
Which of the intervals (-3, 3), [4, 7], (-4, 5], (0,  
 ) and  
[0,
) and  
[0,  )  
are open, closed, both, or neither ?
)  
are open, closed, both, or neither ? 
 
 
 
 
 ) and  
[0,
) and  
[0,  )  
are open, closed, both, or neither ?
)  
are open, closed, both, or neither ? 
 
 
- The interval (-3, 3) is open, because if x is any  
number in (-3, 3), then -3 <  x <  3. or equivalently,  
-3 - x <  0 <  3 - x. Now let  
 = min( 3 + x, 3 - x ).  
Then = min( 3 + x, 3 - x ).  
Then >  0,   
and the interval  
(x - >  0,   
and the interval  
(x - / 2,  
    x + / 2,  
    x + / 2)  
is contained in (-3, 3). In fact, the same argument works for any  
interval of the form (a, b) with a, b real numbers. / 2)  
is contained in (-3, 3). In fact, the same argument works for any  
interval of the form (a, b) with a, b real numbers.
- The interval [4, 7] is closed, because its complement consists  
of the two open sets  
(-  , 4) and  
(7, , 4) and  
(7, ). ).
- The interval (-4, 5] is neither open nor closed. It is not  
open, because the point x = 5 is contained in the set, but  
every neighborhood of that point is not contained inside the set.  
It is not closed, because its complement  
(-  , -4] and  
(5, , -4] and  
(5, ) is not  
open at x = -4. ) is not  
open at x = -4.
- The interval  
(0,  ) and also the  
interval  
(- ) and also the  
interval  
(- , 0) are both open,  
because every point in the set contains a neighborhood contained  
inside the set. , 0) are both open,  
because every point in the set contains a neighborhood contained  
inside the set.
- The interval  
[0,  )  
and also the interval  
(- )  
and also the interval  
(- ,0] are both  
closed, because their complements are the open sets mentioned above. ,0] are both  
closed, because their complements are the open sets mentioned above.
 Interactive Real Analysis
             - part of
            Interactive Real Analysis
             - part of 