Examples 4.2.4(a):
Because | sin(x) | 1
for all real number x, we have that
1 / 2 n sin(n) |But| 1 / 2 n |
![](../../symbols/geom(2).gif)
![](../graphics/sum3.gif)
Note that, formally, we could say: Since
| 1 / 2 n sin(n) |for all n. We also have| 1 / 2 n |
|"Therefore", the series converges absolutely.|
![]()
<
![]()