Examples 1.3.2:
Let A = {1, 2, 3, 4} and B = {a, b, c} and define the following two
relations:
- r : { (a,a), (b,b), (a,b), (b,a) } (on B)
- s : 1 ~ 1, 2 ~ 2, 3 ~ 3, 4 ~ 4, 1 ~ 4, 4 ~ 1, 2 ~ 4, 4 ~ 2 (on A)
- Consider the relation r: { (a,a), (b,b), (a,b), (b,a) }. Then this
is, technically speaking, not an equivalence relation, for the simple
reason that the element c has no association. However, if we restrict our relation
to a new domain that does not include the element c, then it might be
an equivalence relation. We need to check:
- reflexive: every element that has a relation does also have a relation with itself
- symmetric: clearly true
- transitive: follows from the first two in this case.
- Consider the relation s: 1 ~ 1, 2 ~ 2, 3 ~ 3, 4 ~ 4, 1 ~ 4, 4 ~ 1, 2 ~ 4, 4 ~ 2.
Then this is not an equivalence relation. We need to check:
- reflexive: every element with a relation is related to itself.
- symmetric: true as well (3 is only related to 3, so symmetry condition does not apply here)
- not transitive: 1 ~ 4 and 4 ~ 2, but 1 is not related to 2.