Divergence Test
If the series
converges, then the sequence
converges to zero. Equivalently:
This test can never be used to show that a series
converges. It can only be used to show that a series diverges.
Hence, the second version of this theorem is the more important,
applicable statement.


If the sequence
does not converge to zero, then the series
can not converge.
Proof:
Suppose the series does converge. Then it must satisfy the
Cauchy criterion. In other words, given any
> 0 there exists
a positive integer N such that whenever
n > m > N
then
|Let m > N and set n = m. Then the series above reduces to| <
![]()
| a n | <if n > N. That, however, is saying that the sequence![]()
