Example 7.3.3(e): Outer Measure of Intervals
Find the outer measure of the set A of all rational numbers in
[0, 1]. Also show that for any finite collection of
intervals covering A we have that the sum of their lengths is
greater or equal to 1.
First, let's find the outer measure of the set A. The rational
numbers in [0, 1] are countable so we can write the set
A = { r1, r2, r3, ... }.
For each rn define the set
Rn = (rn - 2-n/Then the collection { Rn } is a countable cover of A with open intervals, so it is part of the infimum for computing m*(A). But, rn + 2-n/
)
Therefore m*(A)l(Rn) =
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2-n =
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Well, alright, the above proof is off by a factor 2 or so, but
it does not matter if
m*(A)
or
m*(A)
2
,
so the prove is valid (fix the constants, though).
As for the second part, it is left as an exercise. Compare with some of the previous examples as a hint.