Seton Hall Chemical Hygiene Plan
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Kd = molar concentration of solute in solvent l / molar concentration of solute in solvent 2
is constant, independent of the two individual concentrations but dependent upon the temperature and the nature of the specific solute and solvents involved. Kd is an equilibrium constant called the distribution coefficient. For the iodine-water-cyclohexane system
Kd = [12] in C6H12 / [I2] in H2O
where Kd is now specifically the distribution coefficient (or molar concentration ratio) of iodine
between water and cyclohexane. This type of procedure is used during the common industrial
separation technique known as "extraction." During extraction, compounds are separated by
taking advantage of their different solubilities in each of a pair of immiscible solvents. Drugs and
compounds of plutonium are examples of substances separated and purified using extraction
techniques.
In this experiment, the molar distribution coefficient at room temperature will be determined by chemical analysis of the iodine in a water solution before and after shaking it with cyclohexane. The analysis will be done by titrating these aqueous solutions with sodium thiosulfate solution using starch indicator. The equation for the reaction between iodine and the sodium thiosulfate is
I2 + 2Na2S203 = Na2S406 + 2NaI
(blue with (colorless) (colorless) (colorless)
starch)
In the presence of starch (a small amount of which is added to the solution just before the end of the titration)7 all the reactants and products are colorless except I2, which forms a deep blue complex. The titration is continued until the end-point indicated by the disappearance of the blue color. Solid potassium iodide (KI) is added during the titration to prevent loss of iodine vapor from the open flask. Iodide ion from the KI combines with iodine to form the nonvolatile triiodide ion.
2. Carefully measure 10.0 mL of the iodine solution in a graduated cylinder and transfer to a 250 mL Erlenmeyer flask. Rinse the graduated cylinder with a few milliliters of deionized water and pour the water into the flask. Add a few crystals of potassium iodide (KI). Swirl to dissolve the solid KI.
3. Read the volume of liquid in the buret. Titrate with the thiosulfate solution until the brown color of iodine has become barely perceptible. Add about 1 mL of starch solution and continue adding the thiosulfate solution until the blue color of the starch-iodine complex just disappears. Again read the volume of the liquid in the buret.
4. Clean and dry a large test tube. Carefully measure, with a 25 mL graduated cylinder, 50.0 mL of iodine solution into the test tube. Add 5.0 mL of cyclohexane measured in the same graduated cylinder without washing. Tightly stopper the test tube with a rubber stopper and shake the mixture for about 1 minute, and then allow it to stand for about five minutes.
5. Repeat Step 4 with a second 50.0 mL sample of iodine solution and 8.0 mL of cyclohexane
6. Remove the cyclohexane layer (upper layer) with a Pasteur pipet [CAUTION: its tip is very sharp] from the first test tube into a beaker. Then pour 25.0 mL of the water layer into a clean, dry graduated cylinder. Transfer into a 250 mL Erlenmeyer flask, add a few crystals of KI, and titrate as before with sodium thiosulfate solution. The starch may be added at the beginning of the titration.
7. Repeat with the water layer from the second test tube.
8. Pour the cyclohexane solutions from steps 6 and 7 into the bottle on the side bench labeled ORGANIC WASTE.
1. The thiosulfate solution has been prepared so that 1.00 mL of solution will react with 0.000127
g (5.00 x 10-7 mole) of iodine. Calculate from the volumes of thiosulfate solutions used:
a) the number of moles of iodine in 50 mL of the aqueous iodine solution before shaking with cyclohexane. b) the number of moles of iodine in 50 mL of the aqueous iodine solution after shaking with 5 mL of cyclohexane, and from this the molar concentration of iodine in the water layer. c) same as b) after shaking with 8 mL of cyclohexane. d) the number of moles of iodine in the 5 mL cyclohexane layer and in the 8 mL cyclohexane layer, and the molar concentration of iodine in each of these layers.
For part a), remember that you analyzed a 10 mL sample; for parts b) and c), you analyzed a 25 mL sample.
The results of b) and c) above yield two values for the concentration of iodine in the water layer, and the results of d) yield two values for the concentration of iodine in the cyclohexane layer. From these calculate Kd for the two cases.
Report for each case: the volume of the aqueous layer; the volume of the cyclohexane layer; the concentration of iodine in the aqueous layer; the concentration of iodine in the cyclohexane layer; and the distribution coefficient.
2. Show sample calculations for the work in part 1 above.
3. Review the syllabus and answer the advance study asignment questions for next week's laboratory exercise. Include these answers with your report.
Moles solute in aqueous layer = 34.5 mmol
Moles solute in cyclohexane layer = 145 - 34.5 = 110.5 mmol
molarity = (moles solute)/(volume of solution in liters)
Molarity of solute in aqueous layer = (34.5 x 10-3)/0.0100
= 3.45 molar
Molarity of solute in cyclohexane layer = (110.5 x 10-3)/0.0300
= 3.68 molar
Kd = molar concentration of solute in solvent 1 / molar concentration of solute in solvent 2
Kd = 3.68/3.45 = 1.07 [no units]
2. Write a balanced chemical equation to show the oxidation of sodium thiosulfate by molecular iodine.
3. Write short definitions (25 words or less) for each of the following: a. extraction, b. distribution coefficient, c. equilibrium.
Check the course syllabus for specific schedule information for your lab section.
Adapted with permission from Glanville and Russell, "Experiments in General Chemistry" Virginia Tech Department of Chemistry, 1995.
Copyright 1997, Nicholas H. Snow and Seton Hall University, All Rights Reserved.
(nhs) 1/27/97