Formation of Sulfur Trioxide

S (s) + O2 (g) ----> SO2 (g) DH1 = -296.8 kJ

SO2 (g) + (1/2)O2 (g) ---> SO3 (g) (1/2)DH2 = -99.2 kJ

SUM:

S(s) + SO2(g) + (3/2)O2(g) ---> SO2(g) + SO3(g)

S(s) + (3/2)O2(g) ---> SO3(g)

DH = DH1 + (1/2)DH2 = -296.8 kJ +(-99.2 kJ) = -396.0 kJ

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