To find sets contained in one another is slightly more complicated.
We might try sets of the form
A j = [0, 1 / j] for all j.
Then
A j+1
A j,
but their intersection contains the point {1}.
Let
A j = [j,
).
Then
A j+1
A j,
because [j + 1,
)
[j,
).
But by the Archimedian principle, the intersection of all
sets
is empty.