Consider the series
. Then:
- if
lim sup | a n | 1/n < 1 then the series
converges absolutely.
- if
lim sup | a n | 1/n > 1 then the series
diverges
- if
lim sup | a n | 1/n = 1, this test gives no
information
Compare this test with the Ratio test . Although this root test is more
difficult to apply, it is better than the ratio test in the following
sense: there are series for which the ratio test give no information,
yet the root test will be conclusive. You can also use the root test to
prove the ratio test , but not visa versa.
It is important to remember that when the root test gives 1 as the
answer for the lim sup, then no conclusion at all is possible.
The use of the lim sup rather than the regular limit has the
advantage that we do not have to be concerned with the existence of a
limit. On the other hand, if the regular limit exists, it is the same as
the lim sup, so that we are not giving up anything using the lim sup.
Examples:
-
Does the root test apply to
?
Does the series converge or diverge ?
-
Does the root test apply to
?
Does the series converge or diverge ?
-
Does the series
converge or diverge ?
Proof:
Assume that
lim sup | a n | 1/n < 1:
Because of the properties of the limit superior, we know that there exists
> 0 and
N > 1 such that
- | a n | 1/n <
1 -
for n > N
Raising both sides to the n-th power we have:
- | a n | <
(1 -
) n for
n > N
But the terms on the right hand side form a convergent geometric series . Hence, by the
comparison test the series with terms on the left-hand side will converge absolutely.
The proof for the second case if left as an exercise.
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