Assume that
converges: We have
2k-1 a2k = a2k + a2k + a2k + ... + a2kbecause the sequence is decreasing. Hence, we have that![]()
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Now the partial sums on the right are bounded, by assumption. Hence the partial sums on the left are also bounded. Since all terms are positive, the partial sums now form an increasing sequence that is bounded above, hence it must converge. Multiplying the left sequence by 2 will not change convergence, and hence the series![]()
Assume that
converges: We have
Therefore, similar to above, we get:![]()
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>But now the sequence of partial sums on the right is bounded, by assumption. Therefore, the left side forms an increasing sequence that is bounded above, and therefore must converge.![]()