Example:
The series
converges.
Because | sin(x) |
1
for all real number x, we have that
- | 1 / 2 n sin(n) |
| 1 / 2 n |
But
is
a special case of the geometric series, which converges. Hence,
by the comparison test, the original series
converges
absolutely.
Note that, formally, we could say: Since
| 1 / 2 n sin(n) |
|
1 / 2 n | for all n
we also have
|
|
<
"Therefore", the series converges absolutely.
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(bgw)