If a sequence
is bounded
above, then c = sup(aj) is finite. Moreover, given any
> 0, there exists at least one
integer k such that
ak > c -
(see picture).
If a sequence
is bounded
below, then
c = inf(aj) is finite. Moreover, given any
> 0, there exists at least one
integer k such that
ak < c +
(see picture).
Proof:
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