| aj - a | <Also, there is another integer N' such thatif j > N
| aj - a' | <Then, by the triangle inequality:, if j > N'
| a - a' | < | aj - a | + | aj - a' | <Hence | a - a' | < 2+
= 2
if j > max{N,N'}.
Next, we prove boundedness. Since the sequence converges, we can take any
= 1. Then
| aj - a | < 1 if j > NFix that number N. Then we have that
| aj | < = | aj - a | + | a | < 1 + |a| := P for all j > NBut then define M = max{| aj |, j = 1,.., N, P}. Then | aj | < M for all j, i.e. the sequence is indeed bounded.
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