The first part can be proved easily, if the right hand limit equals f'(c) / g'(c): Since f(c) = g(c) = 0 we have
Taking the limit as x approaches c we get the first result. However, the actual result is somewhat more general, and we have to be slightly more careful. We will use a version of the Mean Value theorem:
Take any sequence {
}
converging to c from above. All assumptions of the generalized
Mean Value theorem are satisfied (check !) on [c,
].
Therefore, for each n there exists a number
in
the interval (c,
)
such that
Taking the limit as n approaches infinity will give the desired result for right-handed limits. The proof is similar for left handed limits and therefore for 'full' limits.
The proof of the last part of this theorem is left as an exercise.